(2y^2)-(2y)-(40)=0

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Solution for (2y^2)-(2y)-(40)=0 equation:


Simplifying
(2y2) + -1(2y) + -1(40) = 0

Remove parenthesis around (2y)
(2y2) + -1 * 2y + -1(40) = 0

Multiply -1 * 2
(2y2) + -2y + -1(40) = 0

Multiply -1 * 40
(2y2) + -2y + -40 = 0

Reorder the terms:
-40 + -2y + (2y2) = 0

Solving
-40 + -2y + (2y2) = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '2'.
2(-20 + -1y + y2) = 0

Factor a trinomial.
2((-4 + -1y)(5 + -1y)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-4 + -1y)' equal to zero and attempt to solve: Simplifying -4 + -1y = 0 Solving -4 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1y = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1y = 0 + 4 -1y = 0 + 4 Combine like terms: 0 + 4 = 4 -1y = 4 Divide each side by '-1'. y = -4 Simplifying y = -4

Subproblem 2

Set the factor '(5 + -1y)' equal to zero and attempt to solve: Simplifying 5 + -1y = 0 Solving 5 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1y = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1y = 0 + -5 -1y = 0 + -5 Combine like terms: 0 + -5 = -5 -1y = -5 Divide each side by '-1'. y = 5 Simplifying y = 5

Solution

y = {-4, 5}

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